SQL中怎么计算工作日，针对这个问题，这篇文章详细介绍了相对应的分析和解答，希望可以帮助更多想解决这个问题的小伙伴找到更简单易行的方法。

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CREATE FUNCTION Time_Span_of_minutes(  

start_day DATETIME,  

end_day DATETIME)  

RETURNS FLOAT 

BEGIN 

            -- 返回按分钟计算两段时间的间隔，采用逐日靠近的方法求解，一天按8小时480分钟计算，周末不计，不考虑法定节假日。  

            -- 如果起始日期在周末，则计算当天时间。  

            DECLARE minutes FLOAT;   

            DECLARE next_day DATETIME;  

            SET minutes=0.0;  

            SET next_day=start_day;  

            IF(TIMESTAMPDIFF(DAY,start_day,end_day)<1.0) THEN 

                    SET minutes=minutes+TIMESTAMPDIFF(MINUTE,start_day,end_day);  

            ELSE 

                    WHILE TIMESTAMPDIFF(DAY,next_day,end_day)>=1.0 DO  

                            IF ((DAYOFWEEK(next_day)=7) OR (DAYOFWEEK(next_day)=1)) THEN 

                                    SET next_day=next_day+INTERVAL 1 DAY;  

                            ELSE 

                                    SET next_day=next_day+INTERVAL 1 DAY;  

                                    SET minutes=minutes+480.0;  

                            END IF;  

                    END WHILE;  

                    SET minutes=minutes+TIMESTAMPDIFF(MINUTE,next_day,end_day);  

                    IF ((DAYOFWEEK(start_day)=7) OR (DAYOFWEEK(start_day)=1)) THEN 

                            SET minutes=minutes+TIMESTAMPDIFF(MINUTE,start_day,CONVERT(CONCAT(SUBSTRING(start_day FROM 1 FOR 10),' 17:30:00'),DATETIME));  

                    END IF;  

            END IF;  

            RETURN minutes;  

END; 

CREATE FUNCTION Time_Span_of_minutes(

start_day DATETIME,

end_day DATETIME)

RETURNS FLOAT

BEGIN

                     -- 返回按分钟计算两段时间的间隔，采用逐日靠近的方法求解，一天按8小时480分钟计算，周末不计，不考虑法定节假日。

                     -- 如果起始日期在周末，则计算当天时间。

                     DECLARE minutes FLOAT;

                     DECLARE next_day DATETIME;

                     SET minutes=0.0;

                     SET next_day=start_day;

                     IF(TIMESTAMPDIFF(DAY,start_day,end_day)<1.0) THEN

                                   SET minutes=minutes+TIMESTAMPDIFF(MINUTE,start_day,end_day);

                     ELSE

                                   WHILE TIMESTAMPDIFF(DAY,next_day,end_day)>=1.0 DO

                                                 IF ((DAYOFWEEK(next_day)=7) OR (DAYOFWEEK(next_day)=1)) THEN

                                                               SET next_day=next_day+INTERVAL 1 DAY;

                                                 ELSE

                                                               SET next_day=next_day+INTERVAL 1 DAY;

                                                               SET minutes=minutes+480.0;

                                                 END IF;

                                   END WHILE;

                                   SET minutes=minutes+TIMESTAMPDIFF(MINUTE,next_day,end_day);

                                   IF ((DAYOFWEEK(start_day)=7) OR (DAYOFWEEK(start_day)=1)) THEN

                                                 SET minutes=minutes+TIMESTAMPDIFF(MINUTE,start_day,CONVERT(CONCAT(SUBSTRING(start_day FROM 1 FOR 10),' 17:30:00'),DATETIME));

                                   END IF;

                     END IF;

                     RETURN minutes;

END;

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文章题目：SQL中怎么计算工作日
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