python如何采集百度搜索结果带有特定URL的链接-创新互联
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成都创新互联公司服务项目包括红桥网站建设、红桥网站制作、红桥网页制作以及红桥网络营销策划等。多年来,我们专注于互联网行业,利用自身积累的技术优势、行业经验、深度合作伙伴关系等,向广大中小型企业、政府机构等提供互联网行业的解决方案,红桥网站推广取得了明显的社会效益与经济效益。目前,我们服务的客户以成都为中心已经辐射到红桥省份的部分城市,未来相信会继续扩大服务区域并继续获得客户的支持与信任!#coding utf-8 import requests from bs4 import BeautifulSoup as bs import re from Queue import Queue import threading from argparse import ArgumentParser arg = ArgumentParser(description='baidu_url_collet py-script by xiaoye') arg.add_argument('keyword',help='keyword like inurl:?id=for searching sqli site') arg.add_argument('-p','--page',help='page count',dest='pagecount',type=int) arg.add_argument('-t','--thread',help='the thread_count',dest='thread_count',type=int,default=10) arg.add_argument('-o','--outfile',help='the file save result',dest='oufile',type=int,default='result.txt') result = arg.parse_args() headers = {'User-Agent':'Mozilla/5.0(windows NT 10.0 WX64;rv:50.0) Gecko/20100101 Firefox/50.0'} class Bg_url(threading.Thread): def __init__(self,que): threading.Thread.__init__(self) self._que = que def run(self): while not self._que.empty(): URL = self._que.get() try: self.bd_url_collet(URL) except Exception,e: print(e) pass def bd_url_collect(self, url): r = requests.get(url, headers=headers, timeout=3) soup = bs(r.content, 'lxml', from_encoding='utf-8') bqs = soup.find_all(name='a', attrs={‘data-click‘:re.compile(r'.'), 'class':None})#获得从百度搜索出来的a标签的链接 for bq in bqs: r = requests.get(bq['href'], headers=headers, timeout=3)#获取真实链接 if r.status_code == 200:#如果状态码为200 print r.url with open(result.outfile, 'a') as f: f.write(r.url + '\n') def main(): thread = [] thread_count = result.thread_count que = Queue() for i in range(0,(result.pagecount-1)*10,10): que.put('https://www.baidu.com/s?wd=' + result.keyword + '&pn=' + str(i)) or i in range(thread_count): thread.append(Bd_url(que)) for i in thread: i.start() for i in thread: i.join() if __name__ == '__main__': main() #执行格式 python aaaaa.py "inurl:asp?id=" -p 30 -t 30
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标题名称:python如何采集百度搜索结果带有特定URL的链接-创新互联
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